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The Picard Maneuver@lemmy.world to Memes@lemmy.ml · 2 years ago

They're not worth it!

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They're not worth it!

lemmy.world

The Picard Maneuver@lemmy.world to Memes@lemmy.ml · 2 years ago
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  • callyral@kbin.social
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    2 years ago

    What’s weirder is that the bottom two are 6 feef apart

    • ImplyingImplications@lemmy.ca
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      2 years ago

      Americans will use anything but metric

      • Grammaton Cleric@lemmy.world
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        2 years ago

        I wouldn’t touch the metric system with a 10-foof pole.

        • Rukmer@lemmy.world
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          2 years ago

          That made me laugh so hard I woke up my cats.

        • Brownian Motion@lemmy.worldBanned from community
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          2 years ago

          The correct answer is 2.58 metres.

      • WtfEvenIsExistence@reddthat.com
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        2 years ago

        deleted by creator

      • rustydomino@lemmy.world
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        2 years ago

        Or analytical geometry, for that matter.

    • assa123@infosec.pub
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      2 years ago

      This actually makes the problem solvable

      edit: in 2-D. Even without the typo it was solvable in 3-D.

    • takeda@kbin.social
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      2 years ago

      deleted by creator

  • blanketswithsmallpox@kbin.social
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    2 years ago

    I’m a little sad nobody has done the correct math and it’s been too long for me to do it off the top of my head lol.

    A2+B2=C^2? What distance are the diagonals if the sides are 6’ apart?

    6x6 + 6x6 = sqrt72 = 8.49’ !

    I did it bois. Ty calculator for sqrt72…

    • Kongpiler@lemm.ee
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      2 years ago

      Now do the conversion factor from feef to feet!

      • TheFriendlyDickhead@lemm.ee
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        2 years ago

        The diagonal is 6ft. The side is 6 ft. So 6² + 6feef² = 6²

        1 feef = 0ft

    • exu@feditown.com
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      2 years ago

      Now, what’s the length of the sides if the diagonals are 6ft?

      • TheFriendlyDickhead@lemm.ee
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        2 years ago

        Thats easy.
        6 * 6 = 36
        36 = a² + b²
        Lets assume a = b
        So a² = 18 = b²
        a = b = 4,2426406871

        • shootwhatsmyname@lemm.ee
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          2 years ago

          What if every initial value is unknown?

      • MrMamiya@feddit.de
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        2 years ago

        Roughly 4.24?

    • Unanimous_anonymous@lemmy.ml
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      2 years ago

      8.49’!~=116699.97’

      I am a human, hear me rar.

  • Kokesh@lemmy.world
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    2 years ago

    It is SO HORRIBLE Stephen Hawking got on his feet.

    • elboyoloco@lemmy.world
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      2 years ago

      *got on his feef

    • SubArcticTundra@lemmy.ml
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      2 years ago

      And out of his grave

  • danc4498@lemmy.world
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    2 years ago

    How many dimensions is that picture though?

  • dyen49k@kbin.social
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    2 years ago

    It’s a tetrahedron, duh

  • yjr4df0708@lemmy.ml
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    2 years ago

    how much is a “feef”

    • The Picard Maneuver@lemmy.worldOP
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      2 years ago

      1 feef is 12 finches

  • WtfEvenIsExistence@reddthat.com
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    2 years ago

    deleted by creator

    • PipedLinkBot@feddit.rocks
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      2 years ago

      Here is an alternative Piped link(s): https://piped.video/thOifuHs6eY

      Piped is a privacy-respecting open-source alternative frontend to YouTube.

      I’m open-source, check me out at GitHub.

  • HumbertTetere@feddit.de
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    2 years ago

    The blokes are obviously at different heights, that’s all.

  • dewritoninja@pawb.social
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    2 years ago

    Kid named tetrahedron

  • Sagrotan@lemmy.world
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    2 years ago

    Why? The diagram is from above and they’re shifted in 3 dimensions. Now draw that. I’m not asking. DRAW IT!

  • Canadian_Cabinet @lemmy.ca
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    2 years ago

    If the 6 feet is from head to head, couldn’t you flip two people upside down?

    • intelati@programming.dev
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      2 years ago

      Ha. I’ve always imagined it as six horizontal feet. Assume the heads are on the ground orientation agnostic

  • CaptionAdam@lemmy.world
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    2 years ago

    I did the math the diagonal distance is ~8.5Ft

    • yetAnotherUser@feddit.de
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      2 years ago

      I think it’s closer to √72 Ft

      • CaptionAdam@lemmy.world
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        2 years ago

        Idk I just punched it in and rounded

  • intrepid@lemmy.ca
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    2 years ago

    Oh! come on! How hard is it to social distance in a tetrahedron?

  • eestileib@sh.itjust.works
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    2 years ago

    What dimensional space are the people arranging themselves in?

    But seriously, this reminds me of a time at my former (FAANG) employer where HR sent out a 40-minute video about not being an asshole and avoiding lawsuits.

    12 minutes or so in, they say “as the number of people in a group increases, the number of potential 1:1 interactions increases exponentially.” I thought “actually n(n-1)/2 but whatever”, and finished the video intending to get on with my life.

    My inbox was FULL of engineers who were irate. “HR have proven themselves to be fools!” “I expect the company to never ask me to waste my time on their bullshit again.” “Once again non-technical people talking out their asses.”

    HR sent a global apology for the error, asked everybody to not watch the video while they fixed it, and released a patched version the next day.

    • chimasterflex@lemmy.world
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      HR should have replied with a “this was a test on how not to be an asshole and you’ve all failed. You must take the whole training again”

  • BCsven@lemmy.ca
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    2 years ago

    No one is mentioning that the math doesn’t work out if the staight line distances are constraints then the diagonals are not correct, and vice versa.

    • juliebean@lemm.ee
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      2 years ago

      i think that is the joke

    • pjhenry1216@kbin.social
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      2 years ago

      You do understand what the Pythagorean theorem is, right?

      • BCsven@lemmy.ca
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        2 years ago

        Exactly what I was pointing out. seems when I added comment the post looked empty to me, but now it looks like I commented late

        • pjhenry1216@kbin.social
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          2 years ago

          It’s in the actual picture. What are you talking about?

          • BCsven@lemmy.ca
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            2 years ago

            As I replied to others, Lemmy glitch on my client end. Post had no comments when I posted and I was surprised nobody was making comments

            • pjhenry1216@kbin.social
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              2 years ago

              Ok. Again. Who posts comments explaining the joke though?

              • BCsven@lemmy.ca
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                2 years ago

                Again, glitch in Jerboa app/ Lemmy on my end. Only upper portion of image was showing and it said No comments yet, so I was curious how it sat so long with nothing. Its working OK now, other than I don’t always get notifications of comment replies and have to go click the original comment to see replies. it’s a bit quirky. i thought about deleting comment after I realized what happened, but meh.

                • nudny ekscentryk@szmer.info
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                  2 years ago

                  but why even point out the joke in the picutre, even if there were no comments?

    • TimeSquirrel@kbin.social
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      No one has to mention because everybody gets it already.

      • takeda@kbin.social
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        2 years ago

        This is actually possible, if 1 feef = 0 feet

        • TheFriendlyDickhead@lemm.ee
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          2 years ago

          Only the bottom line is feef. Would work if the top line was feef too.

    • irmoz@reddthat.com
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      That’s what the whole comment section is discussing. It’s the point of the post

      • BCsven@lemmy.ca
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        2 years ago

        Ah, maybe lemmy glitch, post was empty for me when I made the comment

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